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AHB WRAP address boundaries
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AHB WRAP address boundaries
myarm myarm
over 11 years ago
Note: This was originally posted on 18th June 2008 at
http://forums.arm.com
AMBA spec (v2.0) only shows how the addresses wrap when hsize = 2 (word). Is it because the address boundary remains the same for each WRAP4, WRAP8, and WRAP16 cases? Or, should I re-calculate the wrap boundary based on hsize?
For example, I know from the spec that hsize = 2 and WRAP4 will sequence through addresses like this:
0x4 - 0x8 - 0xC - 0x0
Then, does hsize = 1 (halfword) and WRAP4, mean the sequence should be
0x4 - 0x6 - 0x8 - 0xA (using 4 word boundary)
or
0x4 - 0x6 - 0x0 - 0x2 (using 4 halfword boundary)?
Thanks!
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abc_xyz pqr_def
over 11 years ago
+1
Note: This was originally posted on 2nd December 2008 at http://forums.arm.com As Hemamth case 1 : If Start addr is 0x34, WRAP4, HSize is 2 Total no of bytes is 16 Therefore 4 bit alignment is there So...
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myarm myarm
over 11 years ago
Note: This was originally posted on 18th June 2008 at
http://forums.arm.com
Thank you so much for your detailed explanation. It is now crystal clear to me.
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myarm myarm
over 11 years ago
Note: This was originally posted on 18th June 2008 at
http://forums.arm.com
Thank you so much for your detailed explanation. It is now crystal clear to me.
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