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4-kbyte boundary space

quy truong
Note: This was originally posted on 22nd August 2012 at http://forums.arm.com

Hi there,
when I read AMBA AXI4 specification, the spec shows that "Bursts must not cross 4KB boundaries to prevent them from crossing boundaries between slaves and to limit the size of the address incrementer required within slaves". I don't understand about the boundary of 4KB and the relationship between this boundary to the number of slaves in the system. Can you explain that for me?
Many thanks!
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    Note: This was originally posted on 22nd August 2012 at http://forums.arm.com

    Hi Maheshp,
    Thanks for quick reply.  I understand that when doing a read/write operation, the master needs to send start address, burst size, burst length, burst type information to the slave. The slave uses the start address information and data bus width to calculate the corresponding aligned address. The location can be accessed in this read/write operation is calculated from the start address, burst length, burst size, burst type and is  not permitted to beyond the interval which limited by the aligned address and the aligned address plus 4-KB, right? Please show me more detail about that!
    Many thanks!
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  • 0
    Note: This was originally posted on 22nd August 2012 at http://forums.arm.com

    Hi Maheshp,
    Thanks for quick reply.  I understand that when doing a read/write operation, the master needs to send start address, burst size, burst length, burst type information to the slave. The slave uses the start address information and data bus width to calculate the corresponding aligned address. The location can be accessed in this read/write operation is calculated from the start address, burst length, burst size, burst type and is  not permitted to beyond the interval which limited by the aligned address and the aligned address plus 4-KB, right? Please show me more detail about that!
    Many thanks!
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