SIMULATION

"What I'm Doing Wrong?"

You are not posting any source code, forcing readers to have to guess wildly.

"What I'm Doing Wrong?"

You are not posting any source code, forcing readers to have to guess wildly.

I'm very sorry...
As It doesn't work, I tough maybe it was a mistake of mine, so I've tried to compile the example of analog device, but it still saying that generate 4800 bps.

/*********************************************************************

 Author        : ADI - Apps            www.analog.com/MicroConverter

 Date          : Sept. 2005

 File          : UART2.c

 Hardware      : Applicable to ADuC702x rev H or I silicon
                 Currently targetting ADuC7026.

 Description   : Read part of memory and output through UART (SPM0&1).
                                 The baudrate is calculated with the following formula:

                                        DL = HCLK
                                                _______
                                                Baudrate * 2 *16

                                 A 9600 8-N-1 Hyperterminal window is required to observe
                                 the results.

*********************************************************************/
#include <ADuC7026.h>


void senddata(short);
void delay(int);
char hex2ascii(char);

int main (void)  {

static unsigned short SOMEDATA[1024];
int i;

        GP0CON = 0x10000000;            // enable ECLK output on P0.5

        // configures GPIO to flash LED P4.2
        GP4DAT = 0x04000000;            // P4.2 configured as an output. LED is turned on

        // Setup tx & rx pins on SPM 0 and SPM 1
        GP1CON = 0x011;

     // Start setting up UART at 9600bps
        COMCON0 = 0x080;                        // Setting DLAB
        COMDIV0 = 0x088;                        // Setting DIV0 and DIV1 to DL calculated
        COMDIV1 = 0x000;
        COMCON0 = 0x007;                        // Clearing DLAB

        for (i=0; i <1024; i++)
        {
                SOMEDATA[i]=i;
        }

        while(1)
        {
        for (i=0; i <1024; i++)
        {
                senddata (SOMEDATA[i]);
        }
        GP4DAT ^= 0x00040000;           // Complement P4.2
        delay(2000);
        }
}


void delay (int length)
{
        while (length >=0)
        length--;
}

void senddata(short to_send)
{
        while(!(0x020==(COMSTA0 & 0x020))){}
                COMTX = 0x0A;                                           // output LF
        while(!(0x020==(COMSTA0 & 0x020))){}
                COMTX = 0x0D;                                           // output CR
        while(!(0x020==(COMSTA0 & 0x020))){}
                COMTX = hex2ascii ((to_send >> 8) & 0x0F);
        while(!(0x020==(COMSTA0 & 0x020))){}
                COMTX = hex2ascii ((to_send >> 4) & 0x0F);
        while(!(0x020==(COMSTA0 & 0x020))){}
                COMTX = hex2ascii (to_send & 0x0F);
}


char hex2ascii(char toconv)
{
        if (toconv<0x0A)
        {
                toconv += 0x30;
        }
        else
        {
                toconv += 0x37;
        }

        return (toconv);
}

And finally I can't understand why sends LF and CR.

Thanks!

JuanMa

The source code claims:
DL = HCLK / (Baudrate * 2 *16)

You initialize the baudrate divisor with 0x88.

You haven't specified your HCLK, but is it close to:
0x88 * 9600 * 2 * 16 = 41779200 Hz = 41.8MHz?

What is trange with sending LF and CR? Where you thinking about the order of them? CR+LF is the expected order on a Windows system.

ahhh, I didn't know that about CR+LF. Yes it's 41,8Mhz, but I find the problem! It was PLL Setup, CD it was by default at 1, so cleared it.

Thanks for your attention!!

JuanMa