SIMULATION

"What I'm Doing Wrong?"

You are not posting any source code, forcing readers to have to guess wildly.

I'm very sorry...
As It doesn't work, I tough maybe it was a mistake of mine, so I've tried to compile the example of analog device, but it still saying that generate 4800 bps.

/*********************************************************************

 Author        : ADI - Apps            www.analog.com/MicroConverter

 Date          : Sept. 2005

 File          : UART2.c

 Hardware      : Applicable to ADuC702x rev H or I silicon
                 Currently targetting ADuC7026.

 Description   : Read part of memory and output through UART (SPM0&1).
                                 The baudrate is calculated with the following formula:

                                        DL = HCLK
                                                _______
                                                Baudrate * 2 *16

                                 A 9600 8-N-1 Hyperterminal window is required to observe
                                 the results.

*********************************************************************/
#include <ADuC7026.h>


void senddata(short);
void delay(int);
char hex2ascii(char);

int main (void)  {

static unsigned short SOMEDATA[1024];
int i;

        GP0CON = 0x10000000;            // enable ECLK output on P0.5

        // configures GPIO to flash LED P4.2
        GP4DAT = 0x04000000;            // P4.2 configured as an output. LED is turned on

        // Setup tx & rx pins on SPM 0 and SPM 1
        GP1CON = 0x011;

     // Start setting up UART at 9600bps
        COMCON0 = 0x080;                        // Setting DLAB
        COMDIV0 = 0x088;                        // Setting DIV0 and DIV1 to DL calculated
        COMDIV1 = 0x000;
        COMCON0 = 0x007;                        // Clearing DLAB

        for (i=0; i <1024; i++)
        {
                SOMEDATA[i]=i;
        }

        while(1)
        {
        for (i=0; i <1024; i++)
        {
                senddata (SOMEDATA[i]);
        }
        GP4DAT ^= 0x00040000;           // Complement P4.2
        delay(2000);
        }
}


void delay (int length)
{
        while (length >=0)
        length--;
}

void senddata(short to_send)
{
        while(!(0x020==(COMSTA0 & 0x020))){}
                COMTX = 0x0A;                                           // output LF
        while(!(0x020==(COMSTA0 & 0x020))){}
                COMTX = 0x0D;                                           // output CR
        while(!(0x020==(COMSTA0 & 0x020))){}
                COMTX = hex2ascii ((to_send >> 8) & 0x0F);
        while(!(0x020==(COMSTA0 & 0x020))){}
                COMTX = hex2ascii ((to_send >> 4) & 0x0F);
        while(!(0x020==(COMSTA0 & 0x020))){}
                COMTX = hex2ascii (to_send & 0x0F);
}


char hex2ascii(char toconv)
{
        if (toconv<0x0A)
        {
                toconv += 0x30;
        }
        else
        {
                toconv += 0x37;
        }

        return (toconv);
}

And finally I can't understand why sends LF and CR.

Thanks!

JuanMa

The source code claims:
DL = HCLK / (Baudrate * 2 *16)

You initialize the baudrate divisor with 0x88.

You haven't specified your HCLK, but is it close to:
0x88 * 9600 * 2 * 16 = 41779200 Hz = 41.8MHz?

What is trange with sending LF and CR? Where you thinking about the order of them? CR+LF is the expected order on a Windows system.

ahhh, I didn't know that about CR+LF. Yes it's 41,8Mhz, but I find the problem! It was PLL Setup, CD it was by default at 1, so cleared it.

Thanks for your attention!!

JuanMa