Counting modified bits in a 32bit data word

The problem here was that your task description was insufficiently clear. "Pier"'s reply counts bits the way most people would take "count the bits" to mean.  You mean something quite different.

The problem here was that your task description was insufficiently clear. "Pier"'s reply counts bits the way most people would take "count the bits" to mean.  You mean something quite different.

So bit0 and bit1 have changed.
Now I would have counter[1]++ and counter[0]++;

Sorry for that, ok, I try again…

I have to count bit changes in a 32bit data word, separated for each bit.
Therefore I have 32 distinct counters in an array named counter32[32].

counter32[0] counts bit changes of bit0, counter32[1] counts bit changes of bit1, and so on.

Every time a bit changes, its counter should be incremented.
olddata := 0x00000002; newdata := 0x00000001;
olddata ^ newdata gives 0x00000011, so two bits changed.
Here two bits have changed, bit0 and bit1, so counter32[0]++ and counter32[1]++

Best regards
Juergen

I think something like this.
But this is tooo slow for our needs and I have no knowledge of ARM Assembler...
MCU is a STM32G0 with Cortex-M0+.

uint32_t counter32[32];
olddata = 0x00000001U;
newdata = 0x00000002U;

void CountBits(uint32_t old, uint32_t new)
{
    uint32_t x;
    uint32_t mask = 0x00000001U;
    int      i;

    x = old ^ new;			// x == 0x00000003
    for (i = 0; i < 32; i++)
    {
        if (x & mask)
            counter[i]++;
        mask <<= 1;
    }        
}


void main (void)
{
    CountBits (olddata, newdata);
}