I have to count modified bits in a volatile 32 bit data word.Example:Initial counter32[32] := 0; olddata := 0x00000010; newdata := 0x0000000001;So we have moddata := newdata xor olddata => moddata := 00000011.So bit0 and bit1 have changed.Now I would have counter[1]++ and counter[0]++;How this can be done on a Cortex-M0+ fastes way?Best regards Juergen
Sorry for not (yet) understanding your solution.What is x? What is y?Have to count changed bits.So I have an array of 32 counters (uint32_t counter32 [32];).In my example bit0 and bit1 have changed, so counter32[0] and counter32[1] should be incremented.the result of your popcount32() is something between 0 and 63...Best regardsJuergen
The problem here was that your task description was insufficiently clear. "Pier"'s reply counts bits the way most people would take "count the bits" to mean. You mean something quite different.
So bit0 and bit1 have changed.Now I would have counter[1]++ and counter[0]++;Sorry for that, ok, I try again…I have to count bit changes in a 32bit data word, separated for each bit.Therefore I have 32 distinct counters in an array named counter32[32].
counter32[0] counts bit changes of bit0, counter32[1] counts bit changes of bit1, and so on.Every time a bit changes, its counter should be incremented.olddata := 0x00000002; newdata := 0x00000001;olddata ^ newdata gives 0x00000011, so two bits changed.Here two bits have changed, bit0 and bit1, so counter32[0]++ and counter32[1]++
Best regardsJuergen
I think something like this.But this is tooo slow for our needs and I have no knowledge of ARM Assembler...MCU is a STM32G0 with Cortex-M0+.
uint32_t counter32[32]; olddata = 0x00000001U; newdata = 0x00000002U; void CountBits(uint32_t old, uint32_t new) { uint32_t x; uint32_t mask = 0x00000001U; int i; x = old ^ new; // x == 0x00000003 for (i = 0; i < 32; i++) { if (x & mask) counter[i]++; mask <<= 1; } } void main (void) { CountBits (olddata, newdata); }