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Hi,
I enabled the DWT's watchpoint functions, and when the watchpoint address is written,
there will be a DebugMonitor exception happens.
But if the interrupt is disabled(e.g. use __ASM volatile ("cpsid i" : : : "memory");), then
the exception will not happen.
Can it generate an escalation exception just like other exception, e.g. bus fault?
My chip is cortex-m33. thanks a lot.
Br,
Yingchun
Setting PRIMASK raises priority to 0. So only exceptions with priority < 0 can interrupt. IIRC is the highest priority of the debug exception 0. Thus, cannot happen while PRIMASK is 1.
en, the DebugMonitor trap generated by watch point cannot escalated to a hardfault.
If a synchronous exception with an equal or lower priority value to execution is pending, the PE hardware escalatesit to become a HardFault. This rule applies to all synchronous exceptions and DebugMonitor exceptions that arecaused by the BKPT instruction. This rule does not apply to asynchronous exceptions and all other DebugMonitorexceptions.