Baud rate HELP............

Is this correct:

 LPC_SYSCON->UARTCLKDIV = 0x2;                /* divided by 1 */

LPC_UART->LCR = 0x83;                /* DLB=1, 8 bits, no Parity, 1 Stop bit */
regVal = LPC_SYSCON->UARTCLKDIV;

Fdiv = (((12000000/1)/regVal)/16)/baudrate ;    /*baud rate */

if LPC_SYSCON->UARTCLKDIV = 0x2 means a division by 1, are you then sure that Fdiv = (((12000000/1)/regVal)/16)/baudrate ; will not compute a factor two wrong, since regVal will contain the value 2 and not the value 1.

Is this correct:

 LPC_SYSCON->UARTCLKDIV = 0x2;                /* divided by 1 */

LPC_UART->LCR = 0x83;                /* DLB=1, 8 bits, no Parity, 1 Stop bit */
regVal = LPC_SYSCON->UARTCLKDIV;

Fdiv = (((12000000/1)/regVal)/16)/baudrate ;    /*baud rate */

if LPC_SYSCON->UARTCLKDIV = 0x2 means a division by 1, are you then sure that Fdiv = (((12000000/1)/regVal)/16)/baudrate ; will not compute a factor two wrong, since regVal will contain the value 2 and not the value 1.

I think you can be right.

Update the tested code and post it back.

Hi,

Now I have tried with division value '1', I'm getting 9615 baud rate...

Is this 9615 baud rate is enough for serial communication of 9600?

It's almost perfect. An error of 0.15%.

Most microcontrollers can't get perfect baudrates, but asynchronous communication is designed to support small speed errors.

The requirements to get perfect baudrates are to either have an original clock frequency that divides perfectly, or to have a microcontroller with baudrate correction logic where UART can work with a fractional divisor - it inserts an extra clock cycle now and then to correct for creep caused by the integer division in the "normal" baudrate calculation.