Hello,
i am wondering about stack usage with optimization Level 2. Thread job2 uses 264 Bytes on stack. Obviously much more than required. Using optimization Level 0, stack usage is only 168 Bytes. I thought that escaping scope1 would frees the allocated stack regardless of optimization level, but it isn't.
Is this the purpose of optimazion?
#define ARRAYSIZE1 100 #define ARRAYSIZE2 100 void job2 (void const *argument) { while(1) { int i; { // scop 1 uint8_t array1[ARRAYSIZE1]; for (i = 0; i < ARRAYSIZE1; i++) { array1[i] = reg; // read from reg } for (i = 0; i < ARRAYSIZE1; i++) { reg = array1[i]; // write to reg } } { // scope 2 uint8_t array2[ARRAYSIZE2]; for (i = 0; i < ARRAYSIZE2; i++) { array2[i] = reg; // read from reg } for (i = 0; i < ARRAYSIZE2; i++) { reg = array2[i]; // write to reg } } } }