Hi all, I need a small help regarding L293D. I am making a small project using L293D. Bo motor which hardly consumes 60ma at 5v. i am powering my L293D using a step up circuit 3.7V to 5V from 3.7v li-ion battery. output current from step up circuit is 200ma which is not a issue. my problem is the motor voltage pin no 8 shows me 5.12v. when i drive my motor the voltage accross shows me only 3.00v... due to which the motor drives very slow. can anybody please help why this happen....
what if i use L298N... can it solve my problem.. i have gone through the datasheet of L298N... but sorry did not understood anything
You can normally manage better with a FET-based solution. With two FET with 1 ohm Ron each, the total voltage drop would be 2*1*0.06 V = 120 mV. Or 12 mV if each FET has a Ron of 0.1 ohm.
Bipolar bridges normally has larger voltage drops.
But much FET alternatives expects a larger voltage than 5V to make sure the FET opens/closes fully and doesn't operate as a programmable resistor.