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Pointer Incrementing Warning

Yaswanth Narvaneni

Hi Friends,
I'm Currently working on C51v6.02 developed by Keil, I'm facing a problem with the compiler when I compile a similar code like this

main()
{
   char xdata *Data_Ptr = 0x0000; /* Pointer to the 0x000 location */

   while(some loop)
   *Data_Ptr++; /* Points to the next data location on the RAM-- here 0x0001 */
}
when I compile this it gives the following warning message, 
 .\FILENAME(LINENUMBER): warning C275: FILENAME: expression with possibly no effect

Is there any way to avoid this warning message?? Thank you,

With Regards,
Yaswanth

Proudly wasting time since 1981

Parents
  • 0 in reply to Yaswanth Narvaneni

    Yaswanth,

    " I guess we need to do it this way.

    char xdata *Data_Ptr;
    Data_Ptr = (char *) 0x0000; /* I guess this is the way it must be done */

    /* If done this way */
    Data_Ptr = 0x0000;
    /* you are not type casting it then in that case the compiler should/will give a warning -- Haven't tried it though. */
    "

    There isn't necessary to do casting because it is only initialized pointer to char in xdata memory at location 0.
    Compiler cannot be confused anyway I think. C51 Keil compiler don't generate warning in this case.

    Rest of your question:
    I agree with Mike's last and Andrew's second contribution.

    Vaclav

Reply
  • 0 in reply to Yaswanth Narvaneni

    Yaswanth,

    " I guess we need to do it this way.

    char xdata *Data_Ptr;
    Data_Ptr = (char *) 0x0000; /* I guess this is the way it must be done */

    /* If done this way */
    Data_Ptr = 0x0000;
    /* you are not type casting it then in that case the compiler should/will give a warning -- Haven't tried it though. */
    "

    There isn't necessary to do casting because it is only initialized pointer to char in xdata memory at location 0.
    Compiler cannot be confused anyway I think. C51 Keil compiler don't generate warning in this case.

    Rest of your question:
    I agree with Mike's last and Andrew's second contribution.

    Vaclav

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