Hi,
Taking the code snippet below,
char* ptr = (char*)0x0000; short size = 0x100; short sum = 0x00; do { sum += *ptr++; } while (size--)
This will cause C51 to allocate "ptr" and "size" in RAM.
MOV R3,#00H MOV R2,#00H MOV R1,#00H MOV DPTR,#pre?1251 MOVX @DPTR,PR0 MOV DPTR,#size?1252 MOV A,#01H MOVX @DPTR,A INC DPTR CLR A MOVX @DPTR,A
and everytime "size" is decremented, or "ptr" is incremented, the values are loaded back into the RAM.
Is there a way to force C51 to not use RAM but use the registers only as "ptr" and "size" will never be used anymore after that. What I mean is, is there a way to force C51 to compile to something like this,
mov dptr, #WORD0(00h) mov r4, #01h ; r4:r5 = size mov r5, #00h mov r6, #00h ; r6:r7 = sum mov r7, #00h loop: movx A, @dptr+#000h addw 006h, A ; r6:r7 += A inc dptr subw 004h, 001h ; r4:r5-- jnc loop ; add code to store r6:r7 into RAM
Any advice would be greatly appreciated. Thanks in advance.
Not exactly. Suppose you specify 10 register variables? How many get used depends on the number available. Even worse you only specify 1 register variables. The compiler uses them all then what? An Error? You move some code around an now it is OK. The register keyword never guaranteed that a variable would be in a register. Only that it would be nice if it were.
Is it ANSI required?
"Is it ANSI required?"
The keyword must be processed according to the standard, which means it does mean something gramatically. But most new compilers totally ignore it for the code generation phase.