We are running a survey to help us improve the experience for all of our members. If you see the survey appear, please take the time to tell us about your experience if you can.
Hi,
Taking the code snippet below,
char* ptr = (char*)0x0000; short size = 0x100; short sum = 0x00; do { sum += *ptr++; } while (size--)
This will cause C51 to allocate "ptr" and "size" in RAM.
MOV R3,#00H MOV R2,#00H MOV R1,#00H MOV DPTR,#pre?1251 MOVX @DPTR,PR0 MOV DPTR,#size?1252 MOV A,#01H MOVX @DPTR,A INC DPTR CLR A MOVX @DPTR,A
and everytime "size" is decremented, or "ptr" is incremented, the values are loaded back into the RAM.
Is there a way to force C51 to not use RAM but use the registers only as "ptr" and "size" will never be used anymore after that. What I mean is, is there a way to force C51 to compile to something like this,
mov dptr, #WORD0(00h) mov r4, #01h ; r4:r5 = size mov r5, #00h mov r6, #00h ; r6:r7 = sum mov r7, #00h loop: movx A, @dptr+#000h addw 006h, A ; r6:r7 += A inc dptr subw 004h, 001h ; r4:r5-- jnc loop ; add code to store r6:r7 into RAM
Any advice would be greatly appreciated. Thanks in advance.