Hi,
I use below macro #define SFRX(Sfr,Msk) (Sfr=((Sfr & (~ ((Msk)>>8)) ) |(Msk))) to simply both Set and Reset specified bits in some register.
If I write SFRX ( MyReg , 0x0100 ) this macro clears bit 0. If I write SFRX ( MyReg , 0x0002 ) this macro set bit 1. If I write SFRX ( MyReg , 0x0102 ) this macro clears bit 0 and sets bit 1 in one go whithout affecting other bits.
Now I would like to use this macro for a 32-bits system: #define SREG(Reg,Msk) (Sfr=((Sfr & (~ ((Msk)>>32)) ) |(Msk)))
Although the compiler warns that shifting is too long it works fine. (main.c(56): warning: #63-D: shift count is too large)
My question is: how do I prevent this warning to occur?
Thanks
Henk
The disadvantage is of course that the code is very hard to read, since the code performs a very non-intuitive operation.
Why not instead create (assuming that one motor may need multiple bits):
MaskAndSet(MOTOR_LEFT_MASK|MOTOR_RIGHT_MASK,MOTOR_LEFT_ON|MOTOR_RIGHT_OFF);
or if each motor only have one bit:
MotorsOffOn(MOTOR_RIGHT,MOTOR_LEFT);
Your SFRX #define does not give any indication what it does - at best it looks like it performs a set operation, i.e. Sfr = Msk.
In the general case, you can't just assume that the preprocessor is able to process data of twice the register size. Let's say you have a 64-bit processor where int and long are both 64 bits - why should the preprocessor then support 128-bit integers? Or a 32-bit processor may have 32-bit int and long - why should it have 64-bit support in the preprocessor?