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How to erase memory fields allocated by calloc?

Hi,
I am using calloc in a function to allocate memory to my array. This function writes to the array different number of elements each time the function is called. Here is my problem. Say for the first time function writes to all the 3 locations and next time it writes to only first 2 locations. After the second call, the 3rd memory locations still contains the value written by the first function call. I understand that is the way it works.But I want to know if there is a way to erase all the locations before calling the function again? Is there any built-in function available? Also when I print the values of array initially it doesn't print zeroes. I have read that calloc initializes the memory fields to 0's. Following is the function code.

function write_to_array(int value)
{
 int xdata *ascii_value,i;
 ascii_value = calloc(3, sizeof (int));
 for(i=0;value!=0;i++)
  {
    mod = value%10;
    c = mod+'0';
    ascii_value[i] = toascii(c);
    value/=10;
  }
 }

Parents
  • what we are discussing is not 'C' but design philosophy.

    I have yet to find two persons that can agree fully in that area.

    My philiosophy is 'efficiency' (whatever the cost) and I gather that your philiosophy is 'purity' (whatever the cost).

    so you take the high road and I take the low road but I'll be in Scotland before ye (i.e. faster code)

    Erik

Reply
  • what we are discussing is not 'C' but design philosophy.

    I have yet to find two persons that can agree fully in that area.

    My philiosophy is 'efficiency' (whatever the cost) and I gather that your philiosophy is 'purity' (whatever the cost).

    so you take the high road and I take the low road but I'll be in Scotland before ye (i.e. faster code)

    Erik

Children