Hi, I am using calloc in a function to allocate memory to my array. This function writes to the array different number of elements each time the function is called. Here is my problem. Say for the first time function writes to all the 3 locations and next time it writes to only first 2 locations. After the second call, the 3rd memory locations still contains the value written by the first function call. I understand that is the way it works.But I want to know if there is a way to erase all the locations before calling the function again? Is there any built-in function available? Also when I print the values of array initially it doesn't print zeroes. I have read that calloc initializes the memory fields to 0's. Following is the function code.
function write_to_array(int value) { int xdata *ascii_value,i; ascii_value = calloc(3, sizeof (int)); for(i=0;value!=0;i++) { mod = value%10; c = mod+'0'; ascii_value[i] = toascii(c); value/=10; } }
How can you maintain 'pure' C and go for efficiency?. No, i am not talking about going to assembler (which I do when needed) but things like 'taking advantage' of the library functions.
lowest cost possible is that development cost or unit cost?
Erik
"How can you maintain 'pure' C and go for efficiency?."
They are not mutually exclusive.
"is that development cost or unit cost?
We try to minimize both, but optimizing one typically has the opposite effect on the other.
They are not mutually exclusive. Oh, well, 'pure' may have been the wrong word, I am still, after 10+ years, remembering the "real C" idiot I fired.
"is that development cost or unit cost? We try to minimize both, but optimizing one typically has the opposite effect that seems to be the case in my world too. In a place where I once worked the formula was if [cost of optimizing development calculated at 5 times anticipated time] / ([unit savings] * [anticipated unit count]) came out in favor, then optimize.
"In a place where I once worked the formula was ..."
Or like when they want it "small" and "soon" and "cheap". They can pick only two.
agreed