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comparing signed and unsigned variables

Paul Connor

In the following code:-

char a = 0x80;
unsigned char b = 0x80;

if(a==0x80)
        printf("a==0x80\n");

if(b==0x80)
	printf("b==0x80\n");
The first printf isn't executed but the second is. Why is this? What is the correct way to compare signed variables?
I did think that this might be because the constant was an integer but a=='\x80' produces the same result.

TIA

Paul

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