• State Not Answered
  • Locked Locked
  • Replies 7 replies
  • Subscribers 19 subscribers
  • Views 4255 views
  • Users 0 members are here
Options
How was your experience today?
This discussion has been locked.
You can no longer post new replies to this discussion. If you have a question you can start a new discussion

comparing signed and unsigned variables

Paul Connor

In the following code:-

char a = 0x80;
unsigned char b = 0x80;

if(a==0x80)
        printf("a==0x80\n");

if(b==0x80)
	printf("b==0x80\n");
The first printf isn't executed but the second is. Why is this? What is the correct way to compare signed variables?
I did think that this might be because the constant was an integer but a=='\x80' produces the same result.

TIA

Paul

0