Could you explain the uDMA burst request in Cortex M4F to me?

Hi,

When I read the following on Cortex M4F, I don't understand the blue phrase on the uDMA process.

1. Why does it selects the lesser? The arbitration size matters uDMA services here?

2. I remember that DMA burst cannot be interrupt, even by high priority DMA request. Then what use of the

number of items remaining in the transfer here?

Thanks,

//////////////

9.2.4.2 Burst Request

When a burst request is detected, the μDMA controller transfers the number of items that is the

lesser of the arbitration size or the number of items remaining in the transfer. Therefore, the arbitration

size should be the same as the number of data items that the peripheral can accommodate when

making a burst request. For example, the UART generates a burst request based on the FIFO trigger

level. In this case, the arbitration size should be set to the amount of data that the FIFO can transfer

when the trigger level is reached. A burst transfer runs to completion once it is started, and cannot

be interrupted, even by a higher priority channel. Burst transfers complete in a shorter time than the

same number of non-burst transfers.

Parents
  • Hello,

    what is uDMA? As far as I know, Cortex-M4F does not include it.

    What is the purpose of your question?

    Do you have any troubles?

    By the way, the description would be clear.

    1. Why does it selects the lesser? The arbitration size matters uDMA services here?

    It will be uDMA's convenience.

    2. I remember that DMA burst cannot be interrupt, even by high priority DMA request. Then what use of the

    number of items remaining in the transfer here?

    It depends on the bus architecture. What bus architecture does the uDMA master have?

    The sentence number of items remaining in the transfer would be the DMA burst length itself, I think.


    Best regards,

    Yasuhiko Koumoto.

Reply
  • Hello,

    what is uDMA? As far as I know, Cortex-M4F does not include it.

    What is the purpose of your question?

    Do you have any troubles?

    By the way, the description would be clear.

    1. Why does it selects the lesser? The arbitration size matters uDMA services here?

    It will be uDMA's convenience.

    2. I remember that DMA burst cannot be interrupt, even by high priority DMA request. Then what use of the

    number of items remaining in the transfer here?

    It depends on the bus architecture. What bus architecture does the uDMA master have?

    The sentence number of items remaining in the transfer would be the DMA burst length itself, I think.


    Best regards,

    Yasuhiko Koumoto.

Children
No data