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Manipulate Ram in an LPC4078

Chris84 over 3 years ago

Hello together,

I have an LPC4078. I made measurements with it and everything goes into the RAM. Now I want to manipulate the RAM. Is there a pointer for that? Is the any other possibility?

Thank you and greetings

Chris

Top replies

WestfW over 3 years ago in reply to Chris84 +3 suggested

Pointers are just numbers. uint32_t *src = (uint32_t) 0x20000000; uint32_t *dst = (uint32_t) 0x20010000; uint32_t temp = dest[100]; // save original dest word 100 memcpy(dst, src, 32768); // copy...
Stephen Theobald over 3 years ago +2 suggested

Hi Chris My name is Stephen and I work at Arm. Glad to hear you are making progress with your Cortex-M4-based project. Are you using Arm Development Studio? I'm not sure what you mean by "manipulate the...

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0 WestfW over 3 years ago in reply to Chris84

Pointers are just numbers.

uint32_t *src = (uint32_t) 0x20000000;
uint32_t *dst = (uint32_t) 0x20010000;
uint32_t temp = dest[100];  // save original dest word 100
memcpy(dst, src, 32768); // copy 32k bytes from start of RAM to later in RAM.
dest[100] = temp;  // restore that one word to old value

I believe that all Cortex-M processors have their internal RAM at 0x20000000.

You must of course be careful not to overwrite RAM that is already in use by other code.

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0 WestfW over 3 years ago in reply to Chris84

Pointers are just numbers.

uint32_t *src = (uint32_t) 0x20000000;
uint32_t *dst = (uint32_t) 0x20010000;
uint32_t temp = dest[100];  // save original dest word 100
memcpy(dst, src, 32768); // copy 32k bytes from start of RAM to later in RAM.
dest[100] = temp;  // restore that one word to old value

I believe that all Cortex-M processors have their internal RAM at 0x20000000.

You must of course be careful not to overwrite RAM that is already in use by other code.

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