Hello,
I have a question on axi read time. If we have 20 read commands, the read outstanding is 4 and read latency is 500ns, how much time is needed to read all of these data back?
I feel puzzled on this for a long time and I need a relatively accurate calculate method. Expect your help.
Best Regards,
redbud
Hi Yasuhiko Koumoto,
On the last conclusion of "In this case, the latency would be 500ns x 20." It may be not correct. Would you like to re-analyse it?
Only use read latency, the number of read commands and the numbe of read outstanding, how to compensate for the time of ACLK which is excluded from 500ns latency? (the result may be more accurate).
Hello redbud,
wasn't your assumption that ACLK was too high to be ignored?
What accuracy do you want?
What is your opinion?
Best regards,
Yasuhiko Koumoto.
When the frequency of ACLK was too high and can be ignored, wether the latency would be 500nsx5?
if the latency is 500nsx20, it's equal to the result of one outstanding. So I think it may be not accurate.
In fact, even if the frequency of the ACLK is high, I guess that may have a method to give some compensation on it and which is more accurate than ignore the ACLK when we estimate the total read latency. for example 5.25x500? or something else? Of cause, I just guess it.
Sorry for not explaining it clearly at the last comment.
Thank you for your kindly help!
I am sorry for confusing you.
You are right.
If the ACLK frequency is very high and outstanding is 4, the read latency would be around 500nsx5.