Please note: We are aware of an issue affecting replies on the Arm Community forums, which may not be loading as expected.

We apologize for any inconvenience and appreciate your patience while we investigate and work to resolve the issue.

Thank you for your understanding.


This discussion has been locked.
You can no longer post new replies to this discussion. If you have a question you can start a new discussion

ASR #32

In the SSAT instruction description it says:

ASR #32 Arithmetic right shift by 32 bits, permitted only for encoding A1.

Encoded as sh = 1, immsh = 0b00000.

What does that mean?

Isn't ASR #32 the same as ASR #31?

I understand that it shifts (with "sign extension") the whole 32-bit value out and leaves only the sign extension bits

that are "copies" of the highest bit of the original value.

What am I missing here?