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Hi,
I'm trying to figure out why a registered callback function is failing.
C:socket->cb.socket(socket_idx, 0);
socket->cb.socket(socket_idx, 0);
ASM:It fails at:
00415B88 ldr r3, [r4, #60] 00415B8A mov r1, r11 00415B8C mov r0, r6 -> 00415B8E blx r3 00415B90 b #-676
00415B88 ldr r3, [r4, #60]
00415B8A mov r1, r11
00415B8C mov r0, r6
-> 00415B8E blx r3
00415B90 b #-676
Register r3: 0x00422091
r3
The function it is suppose to jump to is at 0x00422090. So why this extra bit? And why does it get unaligned?
Thanks in advance.
I suggest reading: DDI0403E (Armv7-M reference manual) and/or "The definitve guide to Cortex-M3 and Cortex-M4"Short: Bit 0 indicates the address is a Thumb(-2) one. (Which is of course true for _all_ Cortex-M code addresses.)
42Bastian Schick said:I suggest reading ... "The definitve guide to Cortex-M3 and Cortex-M4"
Absolutely!
https://www.elsevier.com/books/the-definitive-guide-to-arm-cortex-m3-and-cortex-m4-processors/yiu/978-0-12-408082-9
Required reading!