Help! How can I break _DATA_GROUP_ segment into two parts? Thanks!
in assembler: Please read the manual in C split DATA variables into two files
Erik
PS, just curious why?
Whats Please read the manual?
Thanks Erik "PS, just curious why?" Because _DATA_GROUP_ segment too large to be locate behind bit segment, but there is "GAP" afore it.
in C split DATA variables into two files not work.
in C split DATA variables into two files not work. I think I misstated, I just looked (did it a year or do ago and eveidently forgot I did it in assembler like this:
;;//////////////////////////////////////////////////////////////////// ;; ;; FILE: SZDATA.A51 ;; ;; Copyright ;; ;; Overcome the Keil inability to save DATA parts in gropus lexx than "hole" $NOMOD51 PUBLIC GCDXdestListBeg PUBLIC GCDXdestListEnd PUBLIC GCDXprmsListBeg PUBLIC GCDXprmsListEnd PUBLIC GCDXcurrListBeg PUBLIC GCDXcurrListEnd PUBLIC GCDXothListBeg PUBLIC GCDXothListEnd ?DT?zdataf SEGMENT DATA RSEG ?DT?zdataf GCDXdestListBeg: ds 2 GCDXdestListEnd: ds 2 GCDXprmsListBeg: ds 2 GCDXprmsListEnd: ds 2 GCDXcurrListBeg: ds 2 GCDXcurrListEnd: ds 2 GCDXothListBeg: ds 2 GCDXothListEnd: ds 2 end
combined with this in the c
>extern U8DX GCDXdestListBeg; // first used field destinations list extern U8DX GCDXdestListEnd; // first unused field destinations list extern U8DX GCDXprmsListBeg; // first used field pr messages list extern U8DX GCDXprmsListEnd; // first unused field pr messages list extern U8DX GCDXcurrListBeg; // first used field current messages list extern U8DX GCDXcurrListEnd; // first unused field current messages list extern U8DX GCDXothListBeg; // first used field current messages list extern U8DX GCDXothListEnd; // first unused field current messages list // parts of the 'normal' data segment UCDX GCDXdispList_p; // bitmap generator pointer UCDX GCDXdispListWas_p; // bitmap generator pointer
*** ERROR L107: ADDRESS SPACE OVERFLOW SPACE: DATA SEGMENT: _DATA_GROUP_ LENGTH: 000056H * * * * * D A T A M E M O R Y * * * * * * * * 000000H 000007H 000008H --- AT.. DATA "REG BANK 0" 000008H 000010H 000009H BYTE UNIT DATA ?DT?MAIN 000011H 000013H 000003H BYTE UNIT DATA ?DT?KEYBOARD 000014H 00001CH 000009H BYTE UNIT IDATA _IDATA_GROUP_ 00001DH 00001FH 000003H --- --- **GAP** 000020H 000027H 000008H BYTE BITADDR DATA ?BA?MAIN 000028H 000028H 000001H BYTE BITADDR DATA ?BA?BIOCAN 000029H.0 00002AH.0 000001H.1 BIT UNIT BIT ?BI?CONTROL 00002AH.1 00002AH.7 000000H.7 BIT UNIT BIT ?BI?MAIN 00002BH.0 00002BH.2 000000H.3 BIT UNIT BIT _BIT_GROUP_ 00002BH.3 00002BH.4 000000H.2 BIT UNIT BIT ?BI?KEYBOARD 00002BH.5 00002BH 000000H.3 --- --- **GAP** 00002CH 00002CH 000001H BYTE UNIT IDATA ?STACK
Because 00002CH + 000056H > 00007FH, it is overflow. if 000056H is split into 000003H and 000053H, then 000003H fill the "GAP" (00001DH to 00001FH) and 00002CH + 000053H = 00007FH, it will be OK. How can I do that? Be careful: it is _DATA_GROUP_
How can I do that? EXACTLY as i did show you above.
Be careful: it is _DATA_GROUP_ so what, you need two DIFFRENTLY NAMED sgements holding the dats, it is STILL "DATA"
if you can not figute out how to 'adjust' the example to 3 bytes, you should not be playing with this.
here is the proof
REG 0000H 0008H ABSOLUTE "REG BANK 0" REG 0008H 0008H ABSOLUTE "REG BANK 1" DATA 0010H 0010H UNIT ?DT?ZDATAF BIT 0020H.0 0002H.3 UNIT ?BI?SLVMAIN BIT 0022H.3 0001H.4 UNIT _BIT_GROUP_ 0023H.7 0000H.1 *** GAP *** DATA 0024H 0020H UNIT _DATA_GROUP_ DATA 0044H 0015H UNIT ?DT?SLVMAIN DATA 0059H 0006H UNIT ?DT?_CRC8?SLV1WIRE DATA 005FH 0001H UNIT ?DT?SLVIIC DATA 0060H 0001H UNIT ?DT?_MOMMARTY?SLV485 IDATA 0061H 000BH UNIT ?ID?SLVMAIN IDATA 006CH 0001H UNIT ?STACK