ARM2138 need help in LCD 4 bit mode code

Hi i am working on ARM 2138 and trying to interface a 16*2 LCD in 4bit mode. please help me with the same. i cant get the output. some problem in the code. please help!! RS connected to P1.24, enable at P0.7, RW is grounded in my circuit. The data lines are D7- P0.3 , D6- P0.4 , D5-P0.5 , D4-P0.6

#include”lpc213x.h”
#include

#define EN (1<<7)
#define RS (1<PS-Primer 2148<"};
unsigned char msg1[]= {":: LCD Demo! ::"};

int main()
{ PINSEL2 = 0;
PINSEL0 = 0;
IODIR0 = 0x00000078;
IODIR1 = 0x01000000;
lcd_initialise();
lcd_display();
return 0;
}

void lcd_initialise(void)
{

int i=0;
lcd_convert(0x30);
lcd_delay(16);
lcd_convert(0x30);
lcd_delay(16);
lcd_convert(0x30);
lcd_delay(16);
lcd_convert(0x20);
lcd_delay(16);

for(i=0;i<4;i++)
{ IOCLR0 = 0xF << 3;
lcd_cmd(cmd[i]);
lcd_delay(15);

}

}

void lcd_cmd(unsigned char data)
{ IOCLR1 |= RS; //RS
lcd_convert(data);
}

void lcd_delay(unsigned int n)
{ unsigned int i,j;
for(i=0;i<n;i++)
for(j=0;j<12000;j++);
}

void lcd_display (void)
{ int i=0,j=0;
/* first line message */
lcd_cmd(0x80);
lcd_delay(15);

while(msg[i]!='')

{
lcd_delay(15);
lcd_data(msg[i]);
i++;
}

lcd_delay(15);
/* second line message */
lcd_cmd(0xc0);
lcd_delay(15);

while(msg1[j]!='')

{
lcd_delay(5);
lcd_data(msg1[j]);
j++;
}

lcd_delay(15);
}

void lcd_convert(char c)
{

if(c & 0x08) IOSET0 = 1 << 3; else IOCLR0 = 1 << 3;
if(c & 0x04) IOSET0 = 1 << 4; else IOCLR0 = 1 << 4;
if(c & 0x02) IOSET0 = 1 << 5; else IOCLR0 = 1 << 5;
if(c & 0x01) IOSET0 = 1 << 6; else IOCLR0 = 1 << 6;

IOSET0 = EN;
lcd_delay(15);
IOCLR0 = EN;
lcd_delay(15);

if(c & 0x80) IOSET0 = 1 << 3; else IOCLR0 = 1 << 3;
if(c & 0x40) IOSET0 = 1 << 4; else IOCLR0 = 1 << 4;
if(c & 0x20) IOSET0 = 1 << 5; else IOCLR0 = 1 << 5;
if(c & 0x10) IOSET0 = 1 << 6; else IOCLR0 = 1 << 6;

IOSET0 = EN;
lcd_delay(15);
IOCLR0 = EN;
lcd_delay(15);

}

void lcd_data (unsigned char data)
{ IOSET1 |= RS; //0x1000; //RS
lcd_convert(data);
}