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Pass 1 dimensional array in function

Passing any arrays by value or pointer does not work very well.

I can try integrating an array into a structure, but that is not how I would do it.

if I have: frame( unsigned char &mbrtubuf, int &uslen) and the receiving side is :

frame ( unsigned char *somepointer, and int *uslen) neither of the variables are passed

correctly to the function. Prototype is in a header file. Does not work and when it does work

its becomes unstable. Terrible compiler. It should work and I should even have to think

about it. I spend more time on the Compiler then I do on the actual program.

The only way I can get the array into a fucntion is by declaring it external in the function.

Any ideas

Phil

Parents
  • Either doing stuff wrong, or having wrong expectations about how 'C' works - or both!

    As Hans-Bernhard Broeker says, you have not given sufficient information to be able to tell.

    "The function pointers work"

    You are aware, aren't you, of the significant limitations thta C51 places on function pointers...?!

    "It appears that I have many interrupts going on"

    Don't you know?

Reply
  • Either doing stuff wrong, or having wrong expectations about how 'C' works - or both!

    As Hans-Bernhard Broeker says, you have not given sufficient information to be able to tell.

    "The function pointers work"

    You are aware, aren't you, of the significant limitations thta C51 places on function pointers...?!

    "It appears that I have many interrupts going on"

    Don't you know?

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