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UART transmitting interrupt handler

Hello

I am facing a problem in the following code.

code :-

#include "LPC318x.h"
void IRQ_HANDLER(void) __irq
{ PIO_OUTP_SET = 0x7EFFFFFF; PIO_OUTP_SET = 0x7EFFFFFF;
}

int main (void)
{ unsigned int i=0; SYSCLK_CTRL = 0x00000140; HCLKPLL_CTRL = 0x00014024; UARTCLK_CTRL = 0x0F; MIC_ER = 0x000007C0; U5LCR = 0x03; U5CLK = 0x0000020E; UART_CLKMODE = 0x00000550; U5FCR = 0x00; U5IER = 0x07; U3DLL = 27;

while(1) {

U5THR = 0x55; U5THR = 0xAA; }

}

When i enable UART5 interrupt by using MIC_ER interrupt is generated as it should be. But after transmitting the data it jumps to an unusual location
0x000002d4.
But it doesnt go to IRQ handler.
If i don't enable the interrupt using MIC_ER then it executes only while(1) loop.
The main aim of the program is to blink the LED after send data through UART5 as mentioned in the IRQ interrupt handler.

Thank You,

Ankit Thakkar.

Parents
  • HEY
    when i place more than two break points in the program and try to run it. it executes code upto first break point but then the execution stops there. it doesnt go ahead by pressing F5. Even it doesnt go ahead if i press F10 or F11. Thats strange.
    When i debug step by step using F11 it doesnt execute using F5.
    I am doing onchip debugging and ETB module of LPC3180 supports upto two breakpoints at a time only.
    So i dont reach on the exact address location where IRQ starting address is located.

Reply
  • HEY
    when i place more than two break points in the program and try to run it. it executes code upto first break point but then the execution stops there. it doesnt go ahead by pressing F5. Even it doesnt go ahead if i press F10 or F11. Thats strange.
    When i debug step by step using F11 it doesnt execute using F5.
    I am doing onchip debugging and ETB module of LPC3180 supports upto two breakpoints at a time only.
    So i dont reach on the exact address location where IRQ starting address is located.

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