hi,
i'm using uVision3.33 , uC-80c31x2. my question is: I'v initilize buffer array which is been loaded with 24 Byte each interval time. now i want to shift the all array right/left by 1 bit. maybe an example will clarify bettet:
unsigned char array_1[24]; unsigned char array_1[24] = { 0x01,0x02,0x03,0x04,0x05,0x06,0x07,0x08,0x09,0x10,0x11,0x12,0x13,0x14,0x15,0x16,0x17,0x18,0x19,0x20,0x21,0x22,0x23,0x24};
the array's values in the example are just for example. probably the operand '>>' must be use. the result i wish for is: (shifting all the array right only one time)
unsigned char array_1[24] = { 0x00,0x81,0x01,0x82,0x02,.....,0x92};
thanks in advance.
i added this to Per Westermark code so after 192 loops all the array is rotating to its original form.
unsigned char array_1[25] = { 0x01,0x02,0x03,0x04,0x05,0x06,0x07,0x08,0x09,0x10,0x11,0x12,0x13,0x14,0x15,0x16,0x17,0x18,0x19,0x20,0x21,0x22,0x23,0x24,0x00}; for (i = 0; i < sizeof(array_1); i++) { printf("%02bx ",array_1[i]); } printf("\n"); for (j = 0; j < 192; j++) { // Shift all data right one bit, // with carry from lower index. if (array_1[23] & 0x01) { array_1[24] = 0x80; // buffer for exit '1' } for (i = 23; i >= 1; --i) { array_1[i] = (array_1[i]>>1) | ((array_1[i-1]<<7) & 0x80); } //for (i = 0; i < sizeof(array_1); i++) { printf("%02bx ",array_1[i]); } // possibly take care of rotate from last entry too. array_1[0] >>= 1; // insert the '1' to entery point array_1[0] |= array_1[24]; for (i = 0; i < sizeof(array_1); i++) { printf("%02bx ",array_1[i]); } printf("\n"); array_1[24] = 0x00; // reset buffer }
thanks again