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Hi,
There is an application note on using the interrupt vectors in C51 c programming for 8051. It goes like this-
unsigned int int_count; unsigned char second;
void timer0 (void) interrupt 1 using 2 { if (++int_count == 4000) { /* count to 4000 */ second++; /* second counter */ int_count = 0; /* clear interrupt counter */ } }
Can anyone explain what does that "using 2" at the end of the function denote?
I understand that interrupt 1 specifies that this is the ISR for interrupt number for timer0 overflow at adress 000Bh. Does the last keyword "using 2" denote the polling priority of the interrupt?
TIA, Mrunmoy
If you do not mind then I would like to have your contact details, so that i can post my questions to you directly.
and deprive all other members of the information?
discussing through a forum has many purposes, let me mention two 1) others may pick up valueable information. I have learned much by seing information posted I was not aware of and did not even think of asking about. e.g. I have picked up a technique or two where I had no idea that a more efficient way than mine (and many others) "tried and true" method existed. 2) if someone makes a wrong reply it is (almost) immediately corrected.
So, please do not suggest taking this discussion off the forum
Erik