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Hi,
There is an application note on using the interrupt vectors in C51 c programming for 8051. It goes like this-
unsigned int int_count; unsigned char second;
void timer0 (void) interrupt 1 using 2 { if (++int_count == 4000) { /* count to 4000 */ second++; /* second counter */ int_count = 0; /* clear interrupt counter */ } }
Can anyone explain what does that "using 2" at the end of the function denote?
I understand that interrupt 1 specifies that this is the ISR for interrupt number for timer0 overflow at adress 000Bh. Does the last keyword "using 2" denote the polling priority of the interrupt?
TIA, Mrunmoy
Guys,
I think I am lost in your high funda discussions :(
I mean you guys, might be having at least 10-15 years of experience and i am a kid in front of you. You guys are in best position to show me the way. Just show me the way, I'll walk through it.
Pls suggest where should i start then if not the 8051?
B.R, Mrunmoy.