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I am a hardware system/circuit designer attempting to utilize a c8051f330 MCU to save a bunch of hardware in the design of some special test equipment. In an attepmt to learn how to design and implement C code I am using some small test programs. I have been unsuccesful in understanding and clearing a syntax error encountered in my attempt to program an interrupt service routine which uses the overflow of timer0 to generate interrupt 1. The section of the program listing whic has the error is: 69 void timer0_ISR (void) interrupt 1 70 { 71 1 72 1 LED = ~LED 73 1 } *** ERROR C141 IN LINE 73 OF SPECIAL_FLASH_PROGRAM.C: syntax error near '}' 74 75/*------------End of ALL STUFF---------------------*/ Thanks in advance for your help!! It's greatly appreciated. Dennis
how about a semicolon? what is LED defined as? Erik
Eric, The LED was defined earlier in the listing as "sbit LED = P1^3;" I'll try a semicolon after the interrupt fucntion, Then I'll reply as to the results first thing tomorrow as I've got to get to a meeting about 50 miles fron here in about an hour. I wrote this particular code exactly as it was used in an example program included with my Silicon Labs IDE stuff, what I mean to say is that I stole it. Thanks