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There is a BUG in the compilation of a bit definition:
unsigned int bdata my_int; sbit bit15 = my_int ^ 15; sbit bit7 = my_int ^ 7; void main() { my_int = 0x8000; if(bit15) { // Here we shall not appear,as compiller // will be erroneous to check 7-bit of // a variable my_int instead of 15-bit // (as this variable place in memory in // little endian order) // ... } if(bit7) { // oops! we here! // ... } }
"the bible states: One way is to refer to their address (i.e., 0-7FH). The other way is with reference to bytes 20H to 2FH. Thus, bits 0-7 can also be referred to as bits 20.0-20.7, and bits 8-FH are the same as 21.0-21.7, and so on. Erik