How can I see sine wave on logic analyzer?

can you run this code for me

#define BIT0 0
#define BIT1 2
#define BIT2 3
#define BIT3 5
#define BIT4 6
#define BIT5 7
#define BIT6 9
#define BIT7 1
#define BIT8 4

#define LED_OFF P0=12
#define LED_ON P0=7

int main( void )
{ P1 = 0x19;

int count=0;

TMR0 = (1<<BIT3)|(BIT2); // divide by 1024 TMR1 = 1<<BIT7; // enable timer interrupt

sei();

for(;;) { // main loop // single press /* if( get_key_press( 1<<KEY0 )) { if(count<=3) count++; } */ // release after short press: task 1 // long press: task 2

if( get_key_short( 1<<KEY0 )) { if(count<=3) count++; }

if( get_key_long( 1<<KEY0 )) { LED1_OFF; LED2_OFF; LED3_OFF; count = 1; }

switch(count) { case 1: LED1_OFF; LED2_OFF; LED3_OFF; break; case 2: LED2_OFF; LED3_OFF; LED1_ON; break; case 3: LED3_OFF; LED1_OFF; LED2_ON; break; case 4: LED1_OFF; LED2_OFF; LED3_ON; break; }

// single press and repeat
/* if( get_key_press( 1<<KEY0 ) || get_key_rpt( 1<<KEY0 )){ uint8_t i = LED_PORT;

i = (i & 0x07) | ((i << 1) & 0xF0); if( i < 0xF0 ) i |= 0x08; count=0; }
*/ }
}

can you run this code for me

#define BIT0 0
#define BIT1 2
#define BIT2 3
#define BIT3 5
#define BIT4 6
#define BIT5 7
#define BIT6 9
#define BIT7 1
#define BIT8 4

#define LED_OFF P0=12
#define LED_ON P0=7

int main( void )
{ P1 = 0x19;

int count=0;

TMR0 = (1<<BIT3)|(BIT2); // divide by 1024 TMR1 = 1<<BIT7; // enable timer interrupt

sei();

for(;;) { // main loop // single press /* if( get_key_press( 1<<KEY0 )) { if(count<=3) count++; } */ // release after short press: task 1 // long press: task 2

if( get_key_short( 1<<KEY0 )) { if(count<=3) count++; }

if( get_key_long( 1<<KEY0 )) { LED1_OFF; LED2_OFF; LED3_OFF; count = 1; }

switch(count) { case 1: LED1_OFF; LED2_OFF; LED3_OFF; break; case 2: LED2_OFF; LED3_OFF; LED1_ON; break; case 3: LED3_OFF; LED1_OFF; LED2_ON; break; case 4: LED1_OFF; LED2_OFF; LED3_ON; break; }

// single press and repeat
/* if( get_key_press( 1<<KEY0 ) || get_key_rpt( 1<<KEY0 )){ uint8_t i = LED_PORT;

i = (i & 0x07) | ((i << 1) & 0xF0); if( i < 0xF0 ) i |= 0x08; count=0; }
*/ }
}

it gives errors but i did not understand what this code about sorry im new in this thing

hi what errors do you get

is anyone here good to fix them.

It would really help if you guys would read the posting instructions so your source isn't a jumbled mess of lines.

Don't post off topic noise to an existing thread, start a new one.

The sine table looks awful. How exactly did you create this, and how does blasting values to the DAC use the timer to pace the output?

your answer is not the answer to my nquestion. so if you want to insult people please do this somewhere else. as answer to your question this is a homework and i choose 2600Hz frequency. i need to generate a sine wave that has 2600 Hz frequency using timer interrupt. not anything else. Im new in this thing and i might wrote the code wrong. if this, please correct me KINDLY.

this is the code that gives the sine table value. i did run it in matlab and got the values.

clear;
close all;
N=1000;

frekans=2600;
fo=10000;

for i=1:1:N
        x(i)=2047*cos(2*pi*frekans*i/fo);
end
figure; plot(x);

B=input('\nCikis dosyasinin ismi   *.txt = ','s');
fid=fopen(B,'w');
for i=1:1:N
    if (x(i) < 0) x(i)=x(i)+4096; end

    xx= round(x(i));

    if (xx>=4096) xx=xx-4096; end

    %fprintf(fid,'%i \n',xx);
    fprintf(fid,'%4x \n',xx);
end
fclose(fid);

and this is the code i wrote

#include <stdio.h>
#include <ADuC841.h>

sbit LED = 0x0B4;

void timer0(void) interrupt 1 //interrupt no. 1 for Timer 0
{
TH0=0xFC;
TL0=0xFB;
}

void main (void)
{

unsigned code values[50][2]={{0x0F, 0x7F},{0x08, 0x11},{0x01, 0x80},{0x07, 0xBF},{0x0D, 0x87},

{0x08, 0x91},{0x03, 0x68},{0x07, 0x02},{0x0B, 0xB7},{0x09, 0x88}, {0x05, 0x19},{0x05, 0xD4},

{0x0A, 0x2C},{0x0A, 0xE7},{0x06, 0x78}, {0x04, 0x49},{0x08, 0xFE},{0x0C, 0x98},{0x07, 0x6F},

{0x02, 0x79}, {0x08, 0x41},{0x0E, 0x80},{0x07, 0xEF},{0x00, 0x81},{0x08, 0x01}, {0x00, 0x81},

{0x07, 0xEF},{0x0E, 0x80},{0x08, 0x41},{0x02, 0x79}, {0x07, 0x6F},{0x0C, 0x98},{0x08, 0xFE},

{0x04, 0x49},{0x06, 0x78}, {0x0A, 0xE7},{0x0A, 0x2C},{0x05, 0xD4},{0x05, 0x19},{0x09, 0x88},

{0x0B, 0xB7},{0x07, 0x02},{0x03, 0x68},{0x08, 0x91},{0x0D, 0x87}, {0x07, 0xBF},{0x01, 0x80},

{0x08, 0x11},{0x0F, 0x7F},{0x07, 0xFF}};

DACCON = 0x0D;

DAC0H = 0x08; DAC0L = 0x00;

TMOD = 0x01; // mode1 of Timer0
TH0 = 0xFC; // initial values loaded to timer
TL0 = 0xFB;
IE = 0x82; // enable interrupt
TR0 = 1; //start timer

while(1) {

int i;

for ( i = 0 ; i < 50; i++) {

DAC0H = values[i][0];
DAC0L = values[i][1];

}

LED ^= 1;
}
}

#define BIT0 0
#define BIT1 2
#define BIT2 3
#define BIT3 5
#define BIT4 6
#define BIT5 7
#define BIT6 9
#define BIT7 1
#define BIT8 4

You might want to consider rewriting that bit so it looks more artful

Maybe:

#define ZERO  0
#define ONE   2
#define TWO   3
#define THREE 5
#define FOUR  6
#define FIVE  7
#define SIX   9
#define SEVEN 1
#define EIGHT 4