I write a program using the RTX51 Tiny as follow: #include <reg52.h> #include <rtx51tny> #include <stdio.h> void init(void)_task_ 0 { init(); os_create_task(1); os_create_task(2); os_create_task(3); os_delete_task(0); } void task1(void)_task_1 { while(1) { printf(menu);//a big menu in code } } void task2(void)_task_2 { while(1) { printf("just test1"); os_wait(K_TMO,5,0); } } void task3(void)_task_3 { while(1) { printf("Just test2"); os_wait(K_TMO,5,0); } } why task1 was terminated by task2 when it excuting? task2 runs forever and don't allow other tasks to start. task3 never run in this program.Why?
How does task 1 give up the processor so that any other task might run? I kinda figured he had round-robin enabled. But, if not, you are right! Jon