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LPC11C CAN message interrupt

Sven S

I am trying to read messages from CAN bus with LPC11C14 uC. I get interrupt when message is transmitted by other CAN device, but the value of LPC_CAN->INT == (1<<15), so I only get interrupt status but dont get message number. I am not sure whether I need to setup something to actually receive message.

definitions

#define IS_BIT_ENABLED(a,b) (((a) & (1U<<(b)))==(1U<<(b))?1:0)
#define INT_STATUS 15
#define INT_MSG_NUM_MASK 0x3F
#define NO_ERROR_MASK (_BV(0)|_BV(1)|_BV(2))
#define STAT_RX0K 4
#define STAT_EWARN 6
#define STAT_BOFF 7

Here is my interrupt routine

uint32_t stat, canint, msg_no;

canint = LPC_CAN->INT;
if ( IS_BIT_ENABLED(canint, INT_STATUS) ) {
        stat = LPC_CAN->STAT;
        if (IS_BIT_ENABLED(stat, STAT_EWARN)) return;
        if (IS_BIT_ENABLED(stat, STAT_BOFF)) return;
        if (IS_BIT_ENABLED(stat, STAT_RX0K)) {
                if ( (stat & NO_ERROR_MASK) != 0) return;
                while (IS_BIT_ENABLED(canint, INT_STATUS));
                msg_no = canint & INT_MSG_NUM_MASK;
                if ( (msg_no >= 0x01) && (msg_no <= 0x20) ) {
                        LPC_CAN->STAT &= ~STAT_RX0K;
                        processMessage (msg_no);
                        }
                }
        }

and initialisation

LPC_SYSCON->SYSAHBCLKCTRL |= (1<<17);
LPC_SYSCON->PRESETCTRL |= (1<<3);

LPC_CAN->CNTL |= (1<<0); //init
LPC_CAN->CLKDIV = 0x5;  //clock divider by 6 48Mhz/6 = 8Mhz

LPC_CAN->CNTL |= (1<<6); //configuration change enabled
LPC_CAN->BT = 0x2301;  //500kBit/s
LPC_CAN->BRPE = 0x0;
LPC_CAN->CNTL &= ~(1<<6); //configuration change disabled

LPC_CAN->CNTL &= ~(1<<0); //init done

while (LPC_CAN->CNTL & (1<<0));

NVIC_EnableIRQ (CAN_IRQn);

LPC_CAN->CNTL |= (1<<1) | (1<<2) | (1<<3) | (1<<5); //Interrupt enable, Status change int, Error int, disable retransmit

Do I need to "clean" the filter to receive actual msg from the buffer ? I didnt setup filter at all so I would expect that I should see all of the messages on the bus.

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