• State Not Answered
  • Locked Locked
  • Replies 2 replies
  • Subscribers 18 subscribers
  • Views 524 views
  • Users 0 members are here
Options
Related
How was your experience today?
This discussion has been locked.
You can no longer post new replies to this discussion. If you have a question you can start a new discussion

How to let the program normally work(use keil c light LD)

chen Olley

I use keil c to write the program
I have a control signal input 0v,5v,I want to let 2 LD cross light.The action is 0v input->LD1 on(LD2 off)and then 5v input->LD1 off(LD2 off),then 0v input->LD2 ON(LD1 off) and then 5v input->LD2 OFF(LD1 OFF) and continue the action
and a stop signal in the LD1 and LD2 should be all off
0V--> LD1 ON LD2 OFF
5V--> LD1 OFF LD2 OFF
OV--> LD1 OFF LD2 ON
5V--> LD1 OFF LD2 OFF
. .
.

I write a program but it can just light 1 LD and stop signal in the light won't off
my program is as following:

void main(void)
{ SHin=1; //the 0v,5v signal stop=1; //let the stop be input LD1=1; //initial ld1 off LD2=1; // initial ld2 off LDno=0; if (stop==0) { LD1=1; LD2=1; } if(SHin==0) { LDno++; if(LDno>1) LDno=0; } else//(SHin==1) { LD1=1; LD2=1; } if(LDno==0) { LD1=0; LD2=1; } else if(LDno==1) { LD2=0; LD1=1; }
please help me!!
Thank you very much!!

Parents
  • 0 

    void main(void)
{
  SHin=1; //the 0v,5v signal
  stop=1; //let the stop be input
  LD1=1; //initial ld1 off
  LD2=1; // initial ld2 off
  LDno=0;
  if (stop==0)
   {
     LD1=1;
     LD2=1;
   }
  if(SHin==0)
   {
     LDno++;
  if(LDno>1)
     LDno=0;
   }
  else
   {
     LD1=1;
     LD2=1;
   }
  if(LDno==0)
   {
     LD1=0;
     LD2=1;
   }
  else if(LDno==1)
   {
     LD2=0;
     LD1=1;
   }
<\pre>
it will cross light,but it light as 0v->LD1 on LD2 off,5v->LD2 on LD1 off

Reply
  • 0 

    void main(void)
{
  SHin=1; //the 0v,5v signal
  stop=1; //let the stop be input
  LD1=1; //initial ld1 off
  LD2=1; // initial ld2 off
  LDno=0;
  if (stop==0)
   {
     LD1=1;
     LD2=1;
   }
  if(SHin==0)
   {
     LDno++;
  if(LDno>1)
     LDno=0;
   }
  else
   {
     LD1=1;
     LD2=1;
   }
  if(LDno==0)
   {
     LD1=0;
     LD2=1;
   }
  else if(LDno==1)
   {
     LD2=0;
     LD1=1;
   }
<\pre>
it will cross light,but it light as 0v->LD1 on LD2 off,5v->LD2 on LD1 off

Children
No data