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How Char Numbers work??

I am having trouble understanding what happens in the 8051 Memory when numbers are stored as Char types. As I understand it when the letter A is store as a Char type the memory holds 0x41. When the number 191 is stored as a Char Type I would expect the memory to hold 3 Hex digits in a string starting with 0x31 for the number 1. This is not what happens.In fact 191 is stored as 0XBF which is the Hex value for 191. I don't understand why we bother using numbers as Char if they are stored the same way Int types are stored?? Can someone explain this??

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0 Andy Neil over 12 years ago in reply to Andy Neil

Note that the following are all equivalent:

char my_array[2] = { '1','2' };

char my_array[2] = { 0x31,0x32 };

char my_array[2] = { 49,50 };

char my_array[2] = { 061,062 };

char my_array[2] = { 0x31,'2' };

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0 Andy Neil over 12 years ago in reply to Andy Neil

Note that the following are all equivalent:

char my_array[2] = { '1','2' };

char my_array[2] = { 0x31,0x32 };

char my_array[2] = { 49,50 };

char my_array[2] = { 061,062 };

char my_array[2] = { 0x31,'2' };

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0 Don Voth over 12 years ago in reply to Andy Neil

Great this makes sense now THANX
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