I am having trouble understanding what happens in the 8051 Memory when numbers are stored as Char types. As I understand it when the letter A is store as a Char type the memory holds 0x41. When the number 191 is stored as a Char Type I would expect the memory to hold 3 Hex digits in a string starting with 0x31 for the number 1. This is not what happens.In fact 191 is stored as 0XBF which is the Hex value for 191. I don't understand why we bother using numbers as Char if they are stored the same way Int types are stored?? Can someone explain this??
[any segment or other attribute info] char my_str[] = "12",
Note that the above will store a third character too - a '\0' string termination.
[any segment or other attribute info] char my_array[2] = { '1','2' };
No termination character since no C string involved.