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Bootloader Startup.asm code Help

Hi,

I'm starting learning 8051 mcu, came up with the startup code written in assembly.
I have few things I need to know.

Here is the sample startup source code of bootloader:

My questions start with ????? below.


;SOME INITIALIZATION HERE

CSEG    AT      0

?C_STARTUP:     LJMP    Start
                LJMP    ISRApp_ExternalInt0
                LJMP    _WritePageOnFlash
                ds      2 ????? Why reserve 2-bytes?

                LJMP    ISRApp_Timer0
                LJMP    GetP2Value
                ds      2 ????? Why reserve 2-bytes?

                ...

                LJMP    ISRApp_UART1
                ds      10 ????? Why reserve 10-bytes, does it overlap the 8-byte interrupt interval?
                LJMP    ISRApp_SMB1
                ...

CSEG   AT       1400h
Base:                   dw      $
ISRApp_Reset:           lcall   Error ????? Why it calls Error?
ISRApp_ExternalInt0:    lcall   Error
ISRApp_Timer0           lcall   Error

...

ISRApp_UART1            lcall   Error


Error:
      clr EA
Loop:
      jmp Loop


...

END

Also, what I don't understand here is, why it didn't indicate CSEG AT 03h for Interrup 0, CSEG AT 0Bh for Interrup 1, etc. as to what states here http://www.keil.com/support/docs/132.htm?

Hope somebody can lighten me up here.

I used Silabs 8051 mcu w/ keil's C51.

thanks
gee

Parents
  • Sir,

    The calls to "Error" are there for unused interrupts. Their purpose is to catch an unexpected interrupt. That is to say, one that could be generated, but should not be because your code has not enabled it. If it were to occur, you would want to try and catch the unexpected event and maybe report it. The "Error" routine could be used to carry out this trivial, but potentially very useful, operation.

    I trust this response answers your question in a satisfactory manner.

    With kindest regards,

    F. St Jones-Wilson (MILF)

Reply
  • Sir,

    The calls to "Error" are there for unused interrupts. Their purpose is to catch an unexpected interrupt. That is to say, one that could be generated, but should not be because your code has not enabled it. If it were to occur, you would want to try and catch the unexpected event and maybe report it. The "Error" routine could be used to carry out this trivial, but potentially very useful, operation.

    I trust this response answers your question in a satisfactory manner.

    With kindest regards,

    F. St Jones-Wilson (MILF)

Children
  • Sir,

    I trust this response answers your question in a satisfactory manner.
    Thank you very much. Your response answer my question very well.

    And to others who responded my post, I'd like to say thank you all for your time and skills helping others to learn. Very much appreciated.

    regards
    Gee