int averege4( int a , int b , int c , int d ) { return ( averege3 ( a , b , c ) + d) / 2; }
int averege3( int a , int b , int c ) { return ( averege2 ( a , b ) + c) / 2; }
int averege2( int a , int b ) { return ( averege1 ( a ) + b) / 2; }
int averege1( int a ) { return ( 0 + a / 2 ); }
why do the result is wrong?
why did you assume i needed average
so, you do not need average, but you need averege
what is 'averege'
Erik
averege is the name i use for the function.
If every citizen of Farawayistan wrote perfect English nobody would have thought averege ment average.
i will put in your comments to prove i got no help. because you people did not help AT ALL! so, go ahead and stamp your little feet in the floor and, next time, use a name that does not seem like a misspelling of a common term.
yes sir.
next time i will be sure to use the names idoit and stoopid and bighed :)
but i dont stamp my feet. i am happy because i have good working code.