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IRQ Not Firing

Hello,

I am writing an I2C master transmitter object. The problem I am having is that the IRQ Handler for I2C1 is not firing. According to the manual, it should fire after the start condition is sent and the status register is 0x08. When I step through the code with the debugger, the status code is 0x08. I am using an MCB1700 development board. Why is it not firing? Did I not configure something properly? For tests, All I am doing is toggling an LED on when the interrupt fires. Once I solve this problem, I will write the rest of the code.

#include <stdio.h>
#include <LPC17XX.h>
#include "GPIO1Output.h"

GPIO1Output out(P1_28);

__irq void I2C1_IRQHandler(void)
{
        if (LPC_I2C1->I2STAT == 0x08)
        {
             out.Set();
        }
}

int main(void)
{
        // Initialize I2C.
        LPC_PINCON->PINSEL0 = 0x0F;
        LPC_PINCON->PINMODE_OD0 = 0x03;

        NVIC_EnableIRQ(I2C1_IRQn);
        LPC_I2C1->I2CONSET = 0x40;

        LPC_I2C1->I2CONSET = 0x20;
        int status = LPC_I2C1->I2STAT;
}

Parents
  • Where in the ISR did you set your breakpoint?

    If an interrupt doesn't happen, then the single-stepping would normally continue as normal. If the processor does not continue to single-step, then you have to consider problems with stack space for the interrupt, or that you do reach the interrupt but get jumped to another place than you thought. Or that you reach the ISR again and again and again because you don't clear the interrupt.

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  • Where in the ISR did you set your breakpoint?

    If an interrupt doesn't happen, then the single-stepping would normally continue as normal. If the processor does not continue to single-step, then you have to consider problems with stack space for the interrupt, or that you do reach the interrupt but get jumped to another place than you thought. Or that you reach the ISR again and again and again because you don't clear the interrupt.

Children