STEPPER MOTOR QUERY

What do you think happens after your 30 steps?

When the for loop ends - do you think your program will end and your prcessor reach any command line waiting for receiving a new command to run?

You should add an infinite loop at the bottom of the main() function, or your program may (depending on used compiler, architecture, startup file etc) restart again and again and again. That is a major think to think about when developing embedded applications - there are no desktop or command line prompt that will take over if you let the program end.

What do you think happens after your 30 steps?

When the for loop ends - do you think your program will end and your prcessor reach any command line waiting for receiving a new command to run?

You should add an infinite loop at the bottom of the main() function, or your program may (depending on used compiler, architecture, startup file etc) restart again and again and again. That is a major think to think about when developing embedded applications - there are no desktop or command line prompt that will take over if you let the program end.

Thank you very much for the response sir..but if u could write me the code,it'l be helpful sir, me new to electronics field.please do help

but if u could write me the code

You lost soul! You should have immediately asked that instead of giving us the false hope that you actually intend to learn something new.

well i tried my best,tried to use a break,abort and return statements to exit from loop neither of them worked..so pls do help me with the code.

"me new to electronics field"

Are you actually interested in learning how to do this yourself, or do you really just want someone to do it for you?

So long as it's not supposed to be your own work (eg, a school assignment), there's no harm in getting others to do stuff for you; after all, most people are not interested in maintaining & repairing their own cars - so they pay someone else to do it for them.

But there's the key - you will have to be prepared to pay!

There's a list of consultants who can do such stuff here: http://www.keil.com/condb
No doubt you could also find local listings.

well yes ..i would like to do it myself..but i need a little more help..atleast help me as to why arent abort or break any of thes statements not helpin to come out of loop and wat kind of loopin me supposed to use?

Picking 'C' statements at random is not a good way to proceed.

You need to start by laying some basic foundations in embedded programming.

I suggest that you start here: http://www.keil.com/books

See also: www.8052.com/.../174564

Thank you everyone for the help and push..i managed to make my stepper motor stop as intended...HURRAY..this is my updated program:
#include<reg52.h>

#define ST_CNTRL P1;

void delay(void);

void main()
{ unsigned int k,j; for(k=0;k<87;k++) { P1 = 0x66; delay(); P1 = 0xcc; delay(); P1 = 0x99; delay(); P1 = 0x33; delay();

} for(j=0;j<0xff;j++) { for(k=1;k<0xff ;k++)
{ j=0;
P1 =0x00;
} }
}

void delay(void)
{ unsigned int i,j;

for(i = 0; i<0x20; i++) { for(j = 0; j<0x20; j++) { } }
}

What was wrong with just a

while (1) ;

or

for (;;) ;

just before the closing brace of main()? Too simple versions of an infinite loop?

This is most definitely not the most beautiful infinite loop I have seen:

for (j = 0; j < 0xff; j++) {
    for (k = 1; k < 0xff; k++) {
        j = 0;
        P1 = 0x00;
    }
}

But at least you didn't use goto to create the loop.

OH tat worked sir..Thank you very much for the help:)

hi did it work

Just checking if I can post to this thread.