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UART Transmission in LPC2378

Dear all, I am new to LPC2378..Currently i am developing code for sending a character in serial port....Below i mentioned the code what i have written..but this is not working...i am using keil uvision4...Can anybody help me in this code????

This is my code...

#include <LPC23xx.H>
#include <stdio.h>
void delay(int);
int main (void)
{

PCONP |= 0x00000010;
PCLKSEL0 |= 0x00000300;

PINSEL0 |= 0x40000000;                /* Enable TxD1 */
PINSEL1 |= 0x00000001;                /* Enable RxD1 */
U1LCR = 0x83;                         /* 8 bits, no Parity, 1 Stop bit */
U1DLM = 0x00;
U1DLL = 0x34;                         /* 9600 Baud Rate @ 12MHz Clock */
U1FDR = 0x21;        /* U1FDR[[7:4]=MULVAL,U1FDR[[3:0]=DIVADDVAL,for baud rate generation */
U1LCR = 0x03;                          /* DLAB = 0 */
U1FCR = 0x07;                          /* enable TX amp RX FIFO ,clears TX amp RX FIFO */

while(1)
{
      U1THR = 'A';
      while (!(U1LSR && 0x20));
}
}

Parents

0 @Marc Crandall over 14 years ago in reply to Venkatesh V

To implement printf you need to provide the low-level definitions for the c library functions that printf uses.

Here is a simple example for uart:

void uart_write_char(uint8_t byte)
{
    while ((U0LSR & TX_HOLDING_REG_EMPTY) == 0 );
    U0THR = byte;
}

uint8_t uart_read_char(void)
{
    while ((U0LSR & RX_DATA_READY) == 0);
    return (uint8_t)U0RBR;
}

//*************************************************************
//
// C Lib - LOW-LEVEL CHARACTER INPUT AND OUTPUT
//
//*************************************************************

struct __FILE
{
  int handle;
};

/* FILE is typedef’d in stdio.h. */

FILE __stdout;
FILE __stdin;
FILE __stderr;

int fgetc(FILE *f)
{
    /* Your implementation of fgetc(). */
    return uart_read_char();
};
int fputc(int ch, FILE *stream)
{
    uart_write_char((uint8_t)ch);
    return ch;
}

int ferror(FILE *stream)
{
    /* Your implementation of ferror(). */
    return 0;
}
long int ftell(FILE *stream)
{
    /* Your implementation of ferror(). */
    return 0;
}
int fclose(FILE *f)
{
    /* Your implementation of ferror(). */
    return 0;
}
int fseek(FILE *f, long nPos, int nMode)
{
    /* Your implementation of ferror(). */
    return 0;
}
int fflush(FILE *f)
{
    /* Your implementation of ferror(). */
    return 0;
}

Hope this helps...

Reply

0 @Marc Crandall over 14 years ago in reply to Venkatesh V

To implement printf you need to provide the low-level definitions for the c library functions that printf uses.

Here is a simple example for uart:

void uart_write_char(uint8_t byte)
{
    while ((U0LSR & TX_HOLDING_REG_EMPTY) == 0 );
    U0THR = byte;
}

uint8_t uart_read_char(void)
{
    while ((U0LSR & RX_DATA_READY) == 0);
    return (uint8_t)U0RBR;
}

//*************************************************************
//
// C Lib - LOW-LEVEL CHARACTER INPUT AND OUTPUT
//
//*************************************************************

struct __FILE
{
  int handle;
};

/* FILE is typedef’d in stdio.h. */

FILE __stdout;
FILE __stdin;
FILE __stderr;

int fgetc(FILE *f)
{
    /* Your implementation of fgetc(). */
    return uart_read_char();
};
int fputc(int ch, FILE *stream)
{
    uart_write_char((uint8_t)ch);
    return ch;
}

int ferror(FILE *stream)
{
    /* Your implementation of ferror(). */
    return 0;
}
long int ftell(FILE *stream)
{
    /* Your implementation of ferror(). */
    return 0;
}
int fclose(FILE *f)
{
    /* Your implementation of ferror(). */
    return 0;
}
int fseek(FILE *f, long nPos, int nMode)
{
    /* Your implementation of ferror(). */
    return 0;
}
int fflush(FILE *f)
{
    /* Your implementation of ferror(). */
    return 0;
}

Hope this helps...

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