Hi All,
I am implementing 2/3 logic as follows: Three inputs a,b,c. d will hold 2/3 value.
d=(a&b)|(b&c)|(c&d);
whether there is any combitation for 4/5 simillar to this?
a,b,c,d,e are 5 inputs then 4 out of 5 logic will be based on the following 10 combinations.
ab,ac,ad,ae bc,bd,be, cd,ce, de
whether there is any simple way to find 4/5 logic...using |,& and !