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hello everyone, I am reading some code on a system that connect the 8051 with an external ram chip but I have no idea what is going on with the code, I have been struggling on this for quite some time now, just want to see if anyone can point me to the right direction.
the first part i dun understand is how the ram is use
void k6x8008_writebyte (unsigned char hadd,unsigned char madd,unsigned char ladd,unsigned char indat) { RD = 1; WR = 1; k6x8008_laddress(ladd); k6x8008_maddress(madd); k6x8008_din(indat); k6x8008_din(indat); k6x8008_haddress(hadd); WR = 0; WR = 0; WR = 1; k6x8008_haddress(0x00); P0 = 0; WR = 1; }
i don't understand what those ladd, madd or hadd means at all
on the main code this is the part that requires writing data to the ram...
iphadd=((subaddress&HADDBITS)/0x00010000); ipmadd=((subaddress&MADDBITS)/0x00000100); ipladd=((subaddress&LADDBITS)/0x00000001); k6x8008_writebyte(iphadd,ipmadd,ipladd+0x00,0xff); k6x8008_writebyte(iphadd,ipmadd,ipladd+0x01,0xff); k6x8008_writebyte(iphadd,ipmadd,ipladd+0x02,0xff);
why does the coder uses binary division?? and this might be abstract but im also not sure why he is writing 0xff to the ram in the part above
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