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Problem with the bootloader startup file(LPC2378)

Hi

We have two different projects bootloader(without RTX kernal) and Application code (with RTX Kernal).When we laod the bootlaoder and the application code, part of the RAM data will be corrupted.Please guide to resolve this problem.

Software interrupts is not required for the bootlaoder
we have not shifted the interrupt address, we are using the same interrupt address

Meomory mapping is as below
Bootloader 0 - 0x2000
Application code starts from 0x2000

Thank you
Harish

Parents Reply Children
  • Do you mix assembler and C, so the assembler code may garble any unexpected register, either destroying a value or making the processor use the incorrect address when reading/writing a variable?

  • Hi Harish,

    (I don't know much about this.)

    Just curious about what are the below settings of both your bootloader and application?

    UND_Stack_Size EQU 0x00000000
    SVC_Stack_Size EQU 0x00000008
    ABT_Stack_Size EQU 0x00000000
    FIQ_Stack_Size EQU 0x00000000
    IRQ_Stack_Size EQU 0x00000100
    USR_Stack_Size EQU 0x00000400

  • Hi John,

    thanks for your reply

    The settings for the bootloader and applicaiton code are given below

    Bootloader
    UND_Stack_Size EQU 0x00000000
    SVC_Stack_Size EQU 0x00000008
    ABT_Stack_Size EQU 0x00000000
    FIQ_Stack_Size EQU 0x00000000
    IRQ_Stack_Size EQU 0x00000100
    USR_Stack_Size EQU 0x00000400

    Application code
    UND_Stack_Size EQU 0x00000000
    SVC_Stack_Size EQU 0x00000020
    ABT_Stack_Size EQU 0x00000000
    FIQ_Stack_Size EQU 0x00000000
    IRQ_Stack_Size EQU 0x00000100
    USR_Stack_Size EQU 0x00000200

  • Hi

    The memory for variables, arrays of both bootloader and Application code are allocated in the same RAM area,

    Since bootloader is not enabled with the interrupts, The Control will not jump back to the bootloader once the applicaiton code starts running.