I faced the wired situation. I have two questions.
I declared the global variable of structure array type as below. A_TYPE gstXXXX[16];
Then, two functions wanted to look for the address of gstXXXX[1].
Q1) At first function, the address of gstXXX[1] was &gstXXX[0]+1464. But other funtion calculated the address of gstXXX[1] was &gstXXX[0]+1480.
Q2) I declared three structures by the same type. typedef struct A { } typedef struct B { } typedef struct C { }
But the result of sizeof them are different. sizeof(A)=124, sizeof(B)=140, sizeof(C)=124
What happened? I cannot understand them.
Please let me know something, if u have ever experienced this problem.
So the definitions of your A_TYPE data structure seen by those two functions are different.
I declared three structures by the same type. typedef struct A { } typedef struct B { } typedef struct C { }
No, you didn't, because none of those is a declaration of any type. They're all syntax errors.
What happened?
It's really quite obvious: despite your statement, they're not the same type. You made it impossible to find out what the difference actually is by stripping out all the details. Come back here with a reproducible example, and odds are people will be able to point you to the exact difference.
typedef struct A { }; typedef struct B { }; typedef struct C { };
if i declare like dis what may b d space allocated by the compiler for each structure.
does this vary 4m compiler 2 compiler
3
yes
know wate, knot 3. d # z prbly klozr 2 17
Dan Henry, you're a devil :-)
The language is an offshoot of Indlish that I call 'Tardish.