Can someone help me get this to work? I want to be able to receive an input on the serial window and then display that input. The problem is the first text repeats forever with a while loop, and without a loop the program displays text but doesn't respond at all. What am I doing wrong? It seems like this should be simple.
#include<stdio.h> #include <reg51.h> //Used for serial interface int main () { char string [50]; //Required for Serial Interface SCON = 0x52; // serial port configuration TMOD = 0x20; TCON = 0x40; TH1 = 0xf3; // 2403 baudrate @12mhz //while (1) { printf ("Insert sentence: "); gets (string); printf ("Your sentence is: %s",string); //return 0; //} }
Nifty. On the man page for gets the example code is practically the inverse of what I need.
void tst_gets (void) { char buf [21]; do { gets (buf, sizeof(buf)-1); printf ("Input string \"%s\"", buf); } while (buf [0] != '\0'); }
So I try
while(1){ char msg[60]; printf("Type a sentence and press ENTER\n"); while (msg [0] != '\0') {gets (msg, sizeof(msg)-1); //puts(msg); printf("%s\n",msg); } }
Which again just loops the "type a sentence" text. Frustrating.
Where is msg[0] set to '\0'?
Jon
Not sure what you mean. I'm pretty new at programming.
I understand gets() will read a line and put a terminating \0 into the string array. Maybe I'm in over my head. I've been trying to get this to work all week.
Try this.
while(1) { char msg[60]; printf("Type a sentence and press ENTER\n"); gets (msg, sizeof(msg)-1); printf("%s\n",msg); }
Ah, I was close. Thank you.