Hi,
I hope someone can help. Code with comments explaining the problem is shown below.
char const char_set1[42] = {'A','B','C','D','E','F','G','H', 'I','J','K','L','M','N','O','P', 'Q','R','S','T','U','V','W','X', 'Y','Z','.','-','%','/',':','0', '1','2','3','4','5','6','7','8','9',' '}; [I then wish to declare a constant pointer to the array] [The following declaration compiles:] char const* char_set_arrayA = char_set1; [But the following declaration fails:] char const* char_set_arrayB[]={char_set1};
Eventually I need to pass a series of character set arrays into this declaration but I cannot get it to compile with one array element (char_set1).
I would be grateful for any advice as to why
char const* char_set_arrayB[]={char_set1};
is not accepted by the compiler. The compiler reports
"error #28: expression must have a constant value"
Is the const declaration incorrect?
Thanks
John McLane