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whether the following debouncing logic will work well: the total cycle for code is 50ms and each function is executed only once during the cycle.
void main() { signed int deb_Counter=0; while(1) { input(); process(); output(); } } int debounce() { if(key_pressed) { deb_Counter++; } else { deb_Counter--; } if(deb_Counter>10) { deb_Counter=0; return(1); } else { deb_Counter=0; return(0); } }
this code is reffered from web with thanks, karthik
because you have no idea what you're doing - sorry.
void input() { int status=debounce(); }
and
void main() { signed int deb_Counter=0; while(1) {